Okay, the first one is:

f(x)= (-x + 3x^2e^5x)^4 Find f ' (x)

I was able to change it to: 4(-x+3x^2e^5x)^3 times chain rule, and I don't know how to break apart 3xsquared times e to the 5x).

Thank you so much for your help.

The second question is:

f(x) = 2x^2 times ln(arcsin 2x)). Fine f ' (x).

Thank you so much.Calculus Questions (chain rule %26amp; finding f prime of x) I just keep getting wrong. =/?

You have to use the product rule in combination with the chain rule.

So f ' (x) = 4(-x+3x^2e^5x)^3*(-1+6x(e^5x) + 5e^5x*(3x^2))

f ' (2x^2*ln(arcsin 2x)) = 4x(ln(arcsin2x)) + 2x^2 * 1/(arcsin 2x) * 1/(sqrt(1-x^2))

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